10cos^2(x)-5sin^2(2x)+2=

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Solution for 10cos^2(x)-5sin^2(2x)+2= equation:


Simplifying
10cos2(x) + -5sin2(2x) + 2 = 0

Multiply cos2 * x
10cos2x + -5sin2(2x) + 2 = 0

Remove parenthesis around (2x)
10cos2x + -5in2s * 2x + 2 = 0

Reorder the terms for easier multiplication:
10cos2x + -5 * 2in2s * x + 2 = 0

Multiply -5 * 2
10cos2x + -10in2s * x + 2 = 0

Multiply in2s * x
10cos2x + -10in2sx + 2 = 0

Reorder the terms:
2 + 10cos2x + -10in2sx = 0

Solving
2 + 10cos2x + -10in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + 10cos2x + -2 + -10in2sx = 0 + -2

Reorder the terms:
2 + -2 + 10cos2x + -10in2sx = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 10cos2x + -10in2sx = 0 + -2
10cos2x + -10in2sx = 0 + -2

Combine like terms: 0 + -2 = -2
10cos2x + -10in2sx = -2

Add '10in2sx' to each side of the equation.
10cos2x + -10in2sx + 10in2sx = -2 + 10in2sx

Combine like terms: -10in2sx + 10in2sx = 0
10cos2x + 0 = -2 + 10in2sx
10cos2x = -2 + 10in2sx

Divide each side by '10os2x'.
c = -0.2o-1s-2x-1 + in2o-1s-1

Simplifying
c = -0.2o-1s-2x-1 + in2o-1s-1

Reorder the terms:
c = in2o-1s-1 + -0.2o-1s-2x-1

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